What is the slope of the line whose equation is 3x-4y-16=0
a 3/4
b 4/3
c -4
d 3
3/4
solve for y
move -4y to the other side: 4y=3x-16
Divide everything by 4: y=3/4x-4
To find the slope of a line from its equation, we need to rewrite the equation in slope-intercept form, which is in the form y = mx + b, where m represents the slope.
Let's rearrange the given equation in terms of y:
3x - 4y - 16 = 0
-4y = -3x + 16
Divide both sides of the equation by -4 to isolate y:
y = (3/4)x - 4
Now, we can see that the equation is in the form y = mx + b, where m is the coefficient of x, which represents the slope.
In this case, the slope (m) is 3/4.
Therefore, the correct answer is a) 3/4.