Br
|
CH3 - CH2 - CH - CH - CH2 -CH3
|
CH2CH3
How would I name the structure above? Would it be 3-bromo-3-methylpentane?
I meant 3-bromo-3-ethylpentane
The bromine and ethyl group are off the third (CH) not the first (CH3)
No. First, you have some serious problems with what you drew. I see a 6-valent carbon, and two 3-valent carbons.Don't get confused because the carbon turns the corner. The LONGEST chain is the way you want to go and the longest chain is 8 carbons assuming you just didn't add enough H atoms to the middle 3-valent Cs and you added too many Hs to the 6-valent C; therefore, it is an octane. I think everyone would know how to draw the structure from your name; however, it isn't correct. I would name it as 3-bromooctane (with those parameters I named above).
.............Br
.............|
CH3 - CH2 - CH - CH2 -CH3
.............|
..........CH2CH3
This is what I meant to draw. The Br and ethyl group just shifted over after I clicked post answer.
So would this be 3-bromo-3-ethylpentane
OK. I see what has happened. You tried to space it so the Br comes off the third C and the methyl group off the third C but you can't space on the boards, at least not easily. If you put both Br and ethyl groups on the same C atom, then that C atom has too many bonds (you need to take off a H atom) and the C to the right doesn't have enough H atoms). If the Br comes of carbon 4 and the ethyl off carbon 3, then the H atoms are attached correct. At any rate, I still count six C atoms in a line which makes it a hexane. Perhaps I just don't see how you intended to draw it. You can describe it; however, and we can go from there.
CH3 - CH2 - CH (which has a Br and ethyl group off of it) - CH2 - CH3
- so basically the Br and CH2CH3 shift over to the CH
Is that the structure you intended. One CH2 has the ethyl and Br on it which makes too many bonds and the carbon to the right has a CH. I'll bet that is where you want the Br and ethyl group?
yes that's where it would go then. Is the C making too many bonds because I count 5? Should I get rid of the hydrogen?
-------Br
-------|
CH3CH2-CH-CH2CH3
-------|
-------CH2CH3
Let me post this and see how it looks. I think this is what you have been trying to draw.
No, that's not it. Move the Br to the carbon on the right and move the ethyl group to the C on the right.
That will be 3-bromo-3-ethylpentane which I think is what you had at the beginning.
To name the structure provided, follow the IUPAC naming rules for organic compounds:
First, identify the longest continuous chain of carbon atoms, which, in this case, is the chain with 6 carbons.
Next, determine the substituents attached to this chain. In this case, there is a methyl group attached to the third carbon atom and a bromine atom attached to the fourth carbon atom.
Assign a number to each carbon atom in the main chain starting from the end closest to the substituents. In this case, the third carbon from the left (the one with the methyl group attached) will be given the number 3, and the fourth carbon (with the bromine attached) will be given the number 4.
Finally, combine all the information to create the systematic name:
3-bromo-3-methylpentane.
Note: The orientation of the structure you provided is slightly off. In the correct structure, the bromine and methyl should be attached to the same carbon atom.