I am figuring out how much KCL will dissolve in 50 grams of water at sixty degrees, based on a graph. According to the graph, 45 grams of KCL can dissolve at 60 degrees. So I subtracted 45 from 50, and got five. The thing is my book said the answer should be between somewhere between 18 and 25 (the graphs' scales aren't small enough to be exact, so 45 was an estimate. But even if I adjust my 45 number a bit, there is still no way the answer could be 22. What did I do wrong? Thank you for cleaning this up!!
Why did you subtract 50-45? I can't understand what that has to do with the problem. My best guess is that most graphs of solubility give the grams that will dissolve in 100 g water. You don't say what the scale is; look at your graph ans see what volume that 45 g you estimate from the graph is. It may be 100 g solution, too. If it is 100 g water, then 1/2 of 45 or 22.5 would be the solubility in 50 mL water and that would agree with the book's answer. I hope this helps.
yah son
To calculate how much KCL will dissolve in 50 grams of water at 60 degrees, we need to understand the concept of solubility. Solubility is typically represented as the maximum amount of solute (in this case, KCL) that can dissolve in a given amount of solvent (in this case, water) at a specific temperature.
Using the graph provided, we determine that 45 grams of KCL can dissolve at 60 degrees. However, it is important to note that this is the maximum amount that can dissolve in 100 grams of water, not 50 grams. In order to calculate how much can dissolve in 50 grams of water, we need to proportionally adjust the amount.
Let's set up a proportion to solve for X, which represents the amount of KCL that can dissolve in 50 grams of water:
45 grams of KCL / 100 grams of water = X / 50 grams of water
To solve for X, we can cross-multiply:
(45 grams of KCL) * (50 grams of water) = (100 grams of water) * (X)
2250 grams of KCL = 100 grams of water * X
Dividing both sides by 100 grams of water:
(2250 grams of KCL) / (100 grams of water) = X
X ≈ 22.5 grams of KCL
Therefore, based on the given graph, approximately 22.5 grams of KCL can dissolve in 50 grams of water at 60 degrees. This falls within the range of 18 to 25 grams, as suggested by your book.