What is the net ionic equation of AlPO4(s) dissolving in H3O+(aq)
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Did you have a question on this? Did I overlook something?
Please don't post duplicate questions under different names, is is most annoying, and in the end, will do your credibility damage.
no, i didn't post a question on this before but i will look at the other answer.
To determine the net ionic equation for the dissolution of AlPO4(s) in H3O+(aq), we first need to write the balanced equation for the reaction.
The chemical formula for aluminum phosphate is AlPO4, and when it dissolves in water, it dissociates into ions. However, in this case, we are specifically interested in its reaction with H3O+(aq). The H3O+ ion is simply a hydrated form of the hydrogen ion (H+), which is present in acidic solutions.
The balanced equation for the dissolution of AlPO4(s) in H3O+(aq) can be written as follows:
AlPO4(s) + 3H3O+(aq) → Al3+(aq) + PO4^3-(aq) + 3H2O(l)
In this equation, AlPO4(s) reacts with three H3O+ ions to form Al3+ ions, PO4^3- ions, and three water (H2O) molecules.
Now, let's write the net ionic equation. The net ionic equation represents the species that take part in the reaction and omits the spectator ions, which are ions that do not participate in the chemical change. In this case, the spectator ions are the H3O+ ions.
The net ionic equation for AlPO4(s) dissolving in H3O+(aq) is:
AlPO4(s) + 3H3O+(aq) → Al3+(aq) + PO4^3-(aq)
Note that we do not include the water molecules (H2O) in the net ionic equation because they do not undergo any chemical change in this reaction.