How do you do this question? It has to do with dependent events.
There are 2 green marbles, 3 blue marbles and 4 red marbles.
Find the probability for the question below if you pick a marble, do not replace it, then pick a second marble.
Probability of green, then red
Please and thanks!
(2/9)(4/8)=1/9
( Remember that when you take a marble out, the total goes from 9 to 8 )
Thanks so much! One question helped me do the rest!
To find the probability of picking a green marble, not replacing it, and then picking a red marble, you will need to understand the concept of dependent events.
Dependent events are events where the outcome of one event affects the outcome of the other event. In this case, the first event is picking a green marble, and the second event is picking a red marble.
To calculate the probability of dependent events, you multiply the probabilities of each event together.
Step 1: Determine the probability of picking a green marble on the first draw.
There are a total of 9 marbles (2 green, 3 blue, and 4 red), so the probability of picking a green marble on the first draw is 2/9.
Step 2: After picking a green marble, there are now 8 marbles left (including 1 green and 4 red). So, on the second draw, the probability of picking a red marble is 4/8.
Step 3: Multiply the probabilities together.
Probability of green, then red = (2/9) * (4/8) = 8/72 = 1/9
Therefore, the probability of picking a green marble and then a red marble, without replacement, is 1/9.