car accelerates from 0 to 60 mi/hr in a time of 5.8 secs.
a. What is the acceleration of car in m/s squared?
need help setting up the problem, thanks
acceleration
= (speed change)/(time interval)
To get the answer in m/s^2, the speed change of 60 mi/hr must first be converted to m/s.
60 mi/hr = (88 ft/s)*(0.3048 m/ft) = 26.8 m/s
Divide that by 5.8 s for the acceleration in m/s^2
You first need to convert the 60 mi/hr to meters/sec. Then the final velocity - initial velocity / time period will give the average acceleration in that time period.
If the answer was in mi/hr then we'd have (60-0)/5.8 mi/sec^2 = 10.3 mi./hr /sec. We could also convert 60mi/hr to 88ft/sec, then avg. accel = (88-0)/5.8 ft/sec^2 = 15.2 ft/sec^2 would be the average acceleration of the car in going from 0 to 60 mi/hr in that time span. Keep in mind that this is not m/sec^2 as the problem requires.
4.62 m/s squared
To solve the problem, we need to follow these steps:
1. Convert the speed change of 60 mi/hr to meters per second (m/s).
- Use the conversion factor: 1 mi/hr = 0.44704 m/s.
- Multiply the speed change by the conversion factor: 60 mi/hr * 0.44704 m/s = 26.8 m/s.
2. Calculate the acceleration by dividing the speed change by the time interval.
- Acceleration = Speed change / Time interval.
- Speed change = 26.8 m/s.
- Time interval = 5.8 seconds.
- Acceleration = 26.8 m/s / 5.8 s = 4.621 m/s^2.
Therefore, the acceleration of the car is 4.621 m/s^2.