I think I get ionic compounds now. I'm just a bit unsure about my answers for these ones.
4. The cation is Au^3+ and the anion was SiO3subscript^-2. For the compound, I wrote (Au subscript2)subscript SiOsubscript3. Is this correct? Would it be called Gold Silicate then?
5. Fe^2+ cation and Cr2(subscript) O7subscript ^-2. I wrote the compound as FeCr2subscript O7subscript. IS this correct? WOuld it then be called Iron Chromide?
3. What happens if you have an anion without Oxygen in it? FOr example I^-1 How would you name this?
Thanks for your help!!
First it is better to leave the words "subscript" out of the discussion. I know that not being able to write subscripts and superscripts makes chemistry even more confusing but with a little practice we can accommodate it. Second, I think you mean superscript when you sometimes write subscript. For example, I think SiO3^-2 is the silicate you speak of. The -2 is a superscript and we show it with a caret sign. The 3 we understand by mutual consent to be a subscript without writing it in.
For gold silicate I would write it as Au2(SiO3)3.
For iron(II) dichromate I would write it as FeCr2O7. The formula you have is correct; the name you have is not correct.
For Fe^+2 and I^-, the compound is FeI2 and named iron(II) chloride. The older name of ferrous chloride is being phased out.
For Fe^+3 and I^-, I would write FeI3 and name it iron(III) iodide. The older name is ferric iodide.
I hope this answers all of your questions. Thanks for using Jiskha.
4. The cation is Au^3+ and the anion was SiO3subscript^-2. For the compound, I wrote (Au subscript2)subscript SiOsubscript3. Is this correct? Would it be called Gold Silicate then?
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yes 3*2 = 2*3 for neutral salt. I suppose your name for it will do.
5. yes two = two
I think FeCr2O4 is iron chromite. I guess this might be chromate
6. Iodide eg : potassium iodide = KI
Ignore anything I said. DrBob is a chemist.
Great job on learning about ionic compounds! Let's go through your answers and see if they are correct.
4. For the compound with Au^3+ cation and SiO3^2- anion, you wrote (Au subscript2)subscript SiOsubscript3. However, the correct formula should be Au2(SiO3)3. It means that you have two Au^3+ cations combined with three SiO3^2- anions. This compound would be called Gold(III) Silicate, given that Au has a charge of +3. So, your answer is almost correct, except for the parenthesis placement and the fact that you should use Roman numerals to indicate the charge of the cation.
5. For the compound with Fe^2+ cation and Cr2(subscript)O7(subscript)^-2 anion, you wrote the compound as FeCr2subscript O7subscript. However, the correct formula should be FeCr2O7. It means that you have one Fe^2+ cation combined with one Cr2O7^2- anion. This compound would be called Iron(II) Dichromate, given that Fe has a charge of +2. So, your answer is slightly incorrect in terms of the subscript placement.
3. If you have an anion without Oxygen, like I^-1, you would name it as the elemental name of iodine with the suffix "-ide." In this case, I^-1 would be called Iodide. So, the correct name for I^-1 is simply Iodide.
Remember, when writing chemical formulas for ionic compounds, you need to balance the charges of the cation and anion. Additionally, use parentheses when you have more than one polyatomic ion in the compound. Also, use Roman numerals to indicate the charge of the cation if it can vary.
Keep up the good work! Let me know if you have any more questions.