What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant?
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PV=nRT if temp is constant, then one has Boyle's law
P2V2=P1V1
It would help to know V1, and the original pressure.
To determine the new pressure inside the container when the piston is moved to the 1.60 L mark while keeping the temperature constant, you would need to use Boyle's law.
Boyle's law states that at constant temperature, the product of the initial pressure and initial volume is equal to the product of the final pressure and final volume. Mathematically, it can be expressed as:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure
V2 = Final volume
In this case, the initial volume V1 is not given, but we know that the piston is moved to the 1.60 L mark, so V2 = 1.60 L.
Since the temperature is kept constant, we can assume the initial pressure and final pressure are proportional to the initial volume and final volume. Therefore, we can rewrite Boyle's law as:
P1 / V1 = P2 / V2
Now, we can solve for the final pressure P2 by substituting the given information:
P1 / V1 = P2 / 1.60 L
It is important to note that without the initial volume, we cannot directly calculate the new pressure. If you have the initial volume or any other information that can help determine the initial pressure, you can substitute it into the equation to find the final pressure.