# Calculus

How can I find the horizontal asymptote of:

y=e^x/(2e^x+5)

i know you have to do the limit as x approaches infinity... but that is about all i know...

mulitply the numberator and denominator by e^-x

y= e^0/(2e^0 + 5e^-x)

y= 1/(2 + 5e^-x)

now, take lim as x >> int. Notice the e^-x goes to zero.

y= 1/2 as x approaches zero.

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