Three forces acting on an object are given by F1 = ( 1.95i - 1.60j ) N, F2 = ( - 4.50i - 3.25j ) N, and F3 = ( 46.0j ) N. The object experiences an acceleration of magnitude 3.85 m/s2
(a) What is the direction of the acceleration?
(b) What is the mass of the object?
(c) What are the velocity components of the object after 19.0 s?
(a) The direction of the acceleration is the direction of the sum of those three vectors. Add them up. The ratio of the i and j sums will tell you the direction of the acceleration. You will need the components and the magnitude for later questions.
(b) The mass is the net force magnitude divided by the acceleration.
(c) The velocity components will be the acceleration components (net force vector divided by mass) multiplied by 19 seconds.posted by drwls