Can someone help me find the value of B in this expression????

log 64 = Blog 4
5 5

Grrr... sorry about that.

Here's the expression again:

log (base = 5) 64 =B log (base = 5) 4

log 64 (base5) = log 4^b (base5)

so 64 = 4^b
by recognition of 64 as a power of 4, b=3

prove that olg base7(9)*log base5(7)*log base3(5)=2

To find the value of B in the expression log (base = 5) 64 = B log (base = 5) 4, we can start by rewriting the equation in exponential form.

The equation can be written as 5^x = 64, where x is the value inside the logarithm.

To find the value of x, we need to know what power of 5 equals 64.

We can write 64 as the power of 4, because 64 is equal to 4^3.

So, we have 5^x = 4^3.

In order to equate the bases, we can rewrite 5 as 4^2/2, because 5 is equal to 4^2/2.

Now we have (4^2/2)^x = 4^3.

By applying the power of a power rule, we can simplify the left side of the equation to 4^(2x/2) = 4^3.

Since the bases are equal, we can equate the exponents, so we have 2x/2 = 3.

By canceling out the 2 in the numerator and denominator, we get x = 3.

Therefore, B = 3 in the given expression.