i need help solvin this quadratic equation
2x^2+x-6=0
1/3x^2+8x-3=0
Try to factor, then set the factors equal to 0 to find possible solutions for x.
For the first one:
2x^2 + x - 6 = 0
Factors are:
(2x - 3)(x + 2) = 0
Setting the factors equal to 0:
2x - 3 = 0; x = 3/2
x + 2 = 0; x = -2
I hope this will help and is what you were asking.
To solve the second equation, 1/3x^2 + 8x - 3 = 0:
First, let's simplify the equation by multiplying both sides by 3 to eliminate the fraction:
3 * (1/3x^2 + 8x - 3) = 0
x^2 + 24x - 9 = 0
Now, we can try to factor the quadratic equation:
(x - 1)(x + 9) = 0
Setting the factors equal to 0:
x - 1 = 0; x = 1
x + 9 = 0; x = -9
So the solutions to the equation are x = 1 and x = -9.