Math word problem

Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist eho is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?

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  1. The faster cyclist "closes the gap" at a rate of 10 - 6 = 4 miles/hour. The initial lead of the slower cyclist is 3*6 = 18 miles.

    Divide 18 miles by 4 miles/hour for the answer in hours

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    posted by drwls
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