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An electron is accelerated by a constant electric field of magnitude 325 N/C. (a) Find the acceleration of the electron. (m/s^2) (b) Use the equations of motion with constant acceleration to find the electron's speed after 1.05 -
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An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 115 m/s2. What are the magnitude and direction of the electric field. -
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an electron enters the region of a uniform,electric field with 3X10^6m/s and e=200 N/C . the horizontal length of the plates is 0.100m. a) find the acceleration of the electron while it is in the electric field . b) if the -
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An electron enters the region of a uniform electric field between two oppositely charged parallel plates as shown, with an initial velocity of 3 x 106 m/s. The electric field between the plates is measured to be E = 200N/C. The
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An electron with an initial speed of 5.0 โ 105 m/s enters a region in which there is an electric field directed along its direction of motion. If the electron travels 9.0 cm in the field before being stopped, what are the -
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an electron with a speed of 5.00 x 10^8 cm/s enters an electric field of magnitude 1.00 x 10^3 N/C, traveling along field lines in the direction that s its motion. a) How far will the electron travel in the field before stopping -
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The figure below shows an electron passing between two charged metal plates that create an 115 N/C vertical electric field perpendicular to the electronโs original horizontal velocity. (These can be used to change the
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An electron is projected with an initial speed of (1.90x10^6 m/s) into the uniform field between two parallel plates. Assume that the field between the plates is uniform and directed vertically downward, and that the field outside -
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At some instant the velocity components of an electron moving between two charged parallel plates are vx = 1.5 ร 105 m/s and vy = 3.0 ร 103 m/s. Suppose the electric field between the plates is given by In unit-vector notation, -
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The magnetic force (Vector FM)on a particle in a magnetic field is found by Vector FM = Vector I ร Vector B, Vector I is the charge multiplied by the velocity of a charged particle and Vector B the strength of the magnetic field,
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