Arectangular field measures 616metres by 456metres.fencing posts are placed along its sides at equal distances a)what is the distance between the post if they are placed as far apart as possible? b)how many posts are used to fence the field?
c)if one of the posts is kshs 265 ,what is the total cost of all the posts(round off your answer to the nearest thousands)
456 = 8*3*19
616 = 8*7*11 , so the Greatest common factor is 8
Placing posts 8 m apart would allow up to put posts at all the corners
Total perimeter is 2(616+456) = 2144 metres
2144 / 8 = 268
So we need 268 posts.
c) you do it