A 1 kg mass is attached to a vertical spring, stretching it by 10 cm from its equilibrium position. With the spring secured in the same stretched position, the 1 kg mass is removed and replaced with a 0.50 kg mass. If the spring is then released, how high will the 0.50 kg mass rise above the point where it was released?
F=kx
so, half the weight means half the stretch.
so it will only be stretched 5 cm with a 0.5kg mass
That means it will rise 5 cm above its lower location.