A radio signal travels at 3.00⋅10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 3.54⋅10^7 meters? Show your work.
3.54⋅10^7 ÷ (3.00⋅10^8)
= 3.54/3 * 10^7/10^8
= 1.18 * 10^-1
= .118 seconds
v = s / t
t = s / v
v = velicity
s = distance
t = time
In this case:
v = 3 ⋅ 10⁸ m / s
s = 3.54 ⋅ 10⁷ m
t = s / v
t = 3.54 ⋅ 10⁷ m / 3 ⋅ 10⁸
t = ( 3.54 / 3 ) ⋅ 10⁷ / 10⁸
Simmilar as 10⁸ / 10⁷ = 10
10⁷ / 10⁸ = 1 / 10
t = 1.18 ⋅ 1 / 10 =
1.18 / 10 = 0.118 s
To calculate the time it takes for a radio signal to travel from a satellite to the surface of the Earth, we will use the formula: time = distance / speed.
Given:
Speed of radio signal = 3.00⋅10^8 meters per second.
Distance from satellite to Earth's surface = 3.54⋅10^7 meters.
Plugging in the values into the formula:
time = (3.54⋅10^7 meters) / (3.00⋅10^8 meters per second)
Now, let's simplify the expression:
time = (3.54/3.00) * (10^7/10^8) seconds
Simplifying further:
time = 1.18 * 10^-1 seconds
Therefore, it will take approximately 0.118 seconds for a radio signal to travel from the satellite to the surface of Earth.