A college freshman must take a science course, a humanities course, and a mathematics course. If she may select any of 4 science courses, any of 3 humanities courses, and any of 2 mathematics courses, how many ways can she arrange her program?
4*3*2 = 24 different ways to choose,
Not quite sure what you mean by "arrange" but if that involves the order of classes, then
3! ways to schedule her 3 choices, so
24*6 = 144 possible schedules
To find the number of ways the college freshman can arrange her program, we can use the concept of permutations.
First, let's determine the number of ways she can select a science course. Since she can choose from any of the 4 science courses, there are 4 choices.
Next, let's consider the number of ways she can select a humanities course. She has 3 options to choose from.
Finally, for the mathematics course, she can choose from 2 options.
To find the total number of ways she can arrange her program, we simply multiply the number of choices for each course together:
Total number of arrangements = (Number of science courses) x (Number of humanities courses) x (Number of mathematics courses)
Total number of arrangements = 4 x 3 x 2
Total number of arrangements = 24
Therefore, there are 24 different ways the college freshman can arrange her program.