# calc velocity

The velocity function is v(t)=t2−3t+2 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [−3,6].

displacement = ??

distance traveled = ??

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1. v(t) = t^2 - 3t + 2
displacement is
s = ∫[-3,6] (t^2 - 3t + 2) dt = 117/2
distance is
∫[-3,6] |t^2 - 3t + 2| dt = 353/6

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