Ask questions and get helpful responses.
Ask a New Question
  1. Questions

calc velocity

The velocity function is v(t)=t2−3t+2 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [−3,6].

displacement = ??

distance traveled = ??

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
revan

  1. v(t) = t^2 - 3t + 2
    displacement is
    s = ∫[-3,6] (t^2 - 3t + 2) dt = 117/2
    distance is
    ∫[-3,6] |t^2 - 3t + 2| dt = 353/6

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    oobleck

Respond to this Question

First Name

Your Response

Similar Questions

  1. Calculus

    The displacement (in centimeters) of a particle s moving back and forth along a straight line is given by the equation s = 3 sin(𝜋t) + 3 cos(𝜋t), where t is measured in seconds. (Round your answers to two decimal places.)

  2. CALCULUS PLEASE HELP!!!

    SHOW WORK PLEASE!!! The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin πt + 3 cos πt, where t is measured in seconds. (Round your answers to

  3. calculus

    a particle moves along a straight line and has an acceleration given by a(t) = 6t+4 where a is measured in cm/sec^2. Its initial velocity is -6 cm/sec. Initially it sits 9 cm to the right of the origin. Find its displacement

  4. calculus

    the position of a particle moving along a coordinate line is s=√(1+4t) , with s in metres and t in seconds. Find the particle's velocity and acceleration at t=6 sec

  1. Calculus

    The velocity function (in meters per second) is given for a particle moving along a line. v(t) = 3t − 7, 0 ≤ t ≤ 3 (a) Find the displacement. -7.5 m (b) Find the distance traveled by the particle during the given time

  2. physics

    the motion of a particle along a straight line is described by the function x=(2t-3)^2 where x is in metres and t is in seconds. A)find the position ,veocity and acceleration at t=2 sec. B) find the velocity of the particle at

  3. calculus

    The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin(πt) + 2 cos(πt), where t is measured in seconds. (Round your answers to two decimal

  4. calculus

    5. A particle moves along the y – axis with velocity given by v(t)=tsine(t^2) for t>=0 . a. In which direction (up or down) is the particle moving at time t = 1.5? Why? b. Find the acceleration of the particle at time t= 1.5. Is

  1. physics

    A particle is moving along a straight line and its position is given by the relation x=(t3- 6t2- 15t+40) m FIND a) The time at which velocity is Zero, b) Position and displacement of the particle at that point. c) Acceleration for

  2. math

    A particle is traveling along a one-dimensional path (such as a number line). The position of the particle is governed by the time function x(t) ƒ­ 3t 4 ƒ{16t3 ƒy18t 2 ƒy 2 , where t is in minutes and 0 „T t „T 5 . Answer

  3. Physics

    A particle is moving along a straight line and its position is given by the relation x=( t3-6t2-15t+40)mm. Find:- (a). The time at which velocity is zero. (b). Position & displacement of the particle at that point. (c).

  4. physics

    A particle is moving along a straight line and its position is given by the relation x=( t3-6t2-15t+40)mm. Find:- (a). The time at which velocity is zero. (b). Position & displacement of the particle at that point. (c).

Still need help? You can ask a new question.