Sulfur trioxide reacts with water to form sulfuric acid according to the following reaction : SO3 + H2O -> H2SO4 Given the atomic mass of hydrogen is 1 amu, the atomic mass of oxygen is 16 amu, and one molecule of sulfuric acid has a mass of 98 amu, what is the atomic mass of sulfur trioxide?
-116amu
-80amu
-48amu
-32amu
All of the amu's must add to 98.
2*H + S + 4*O = 98
2*1 + S + 4*16 = 98
2 + S + 64 = 98
S = 98 - 64 - 2 = ?
S = ?
Yeah 32 is not correct
No, 32 for S is correct. You need that to figure SO3. I assumed you could do the remainder. If S is 32 and O is 16 each then 32 + 3*16 = 32 + 48 = ?
To find the atomic mass of sulfur trioxide (SO3), we need to calculate the sum of the atomic masses of sulfur and three oxygen atoms.
The atomic mass of sulfur (S) is usually given as 32 amu. The atomic mass of oxygen (O) is 16 amu.
So, the atomic mass of sulfur trioxide can be calculated as follows:
Atomic mass of SO3 = (Atomic mass of S) + (3 * Atomic mass of O)
= 32 amu + (3 * 16 amu)
= 32 amu + 48 amu
= 80 amu
Therefore, the atomic mass of sulfur trioxide (SO3) is 80 amu.