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A father is now three times as old as his son. In five years the sum of their age will be 58 years. Find their present ages

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  2. f = father's present ages

    s = son's present ages

    A father is now three times as old as his son means:

    f = 3 s

    In five years father will be f + 5 yrs old, son will be s + 5 yrs old.

    The sum of their age will be 58 years means:

    f + 5 + s + 5 = 58

    f + 10 + s = 58

    Subtract 10 to both sides

    f + s = 48

    Replace f by 3 s in this equation

    3 s + s = 48

    4 s = 48

    s = 48 / 4 = 12

    f = 3 s = 3 ∙ 12 = 36

    Father is now 36 yrs old.

    Son is now 12 yrs old.

    Check result.

    A father is now three times as old as his son:

    f / s = 36 / 12 = 3

    In five years the sum of their age will be 58 years:

    36 + 5 + 12 + 5 = 41 + 17 = 58

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