A father is now three times as old as his son. In five years the sum of their age will be 58 years. Find their present ages
Arswer
f = father's present ages
s = son's present ages
A father is now three times as old as his son means:
f = 3 s
In five years father will be f + 5 yrs old, son will be s + 5 yrs old.
The sum of their age will be 58 years means:
f + 5 + s + 5 = 58
f + 10 + s = 58
Subtract 10 to both sides
f + s = 48
Replace f by 3 s in this equation
3 s + s = 48
4 s = 48
s = 48 / 4 = 12
f = 3 s = 3 ∙ 12 = 36
Father is now 36 yrs old.
Son is now 12 yrs old.
Check result.
A father is now three times as old as his son:
f / s = 36 / 12 = 3
In five years the sum of their age will be 58 years:
36 + 5 + 12 + 5 = 41 + 17 = 58
To solve this problem, we need to set up equations based on the information given.
Let's assume the son's age is x.
According to the question, the father is three times as old as his son, so the father's age can be represented as 3x.
In five years, the son's age will be x + 5, and the father's age will be 3x + 5.
The question also states that in five years, the sum of their ages will be 58. So, we can set up the equation:
(x + 5) + (3x + 5) = 58
Now we can solve this equation:
Combining like terms, we have:
4x + 10 = 58
Subtracting 10 from both sides of the equation:
4x = 48
Dividing both sides by 4:
x = 12
So, the son's present age is 12.
Using this value, we can find the father's age:
Father's age = 3 * 12 = 36
Therefore, the son is currently 12 years old, and the father is currently 36 years old.