Include an explanation, balanced chemical equation, units, significant figures and/or calculations where appropriate.
Standardization of NaOH Solution
Trial 1:
0.501 g KHC8H4O4
15.22 mL NaOH
Trial 2:
0.503 g KHC8H4O4
15.11 mL
Trial 3:
0.500 g KHC8H4O4
15.10 mL
Using the data presented above, calculate the concentration of your standard sodium hydroxide solution. Include the calculation for each trial and the average.
Are you asking me to do your homework? or your lab work? Tell me what you don't understand and I can help you through it.
I'm not sure how to start it.
I know I need to have a balanced chemical equation, so...
KHC8H4O4 (aq) + NaOH (aq) --> H2O (l) + ????
Then once I figure this out, do I use the mass in each trial to find the moles of NaOH through stoichiometry.
Then divide the number of moles by the volume of NaOH.
??
Simplify the KHC8H4O4 to KHT.
Then KHT + NaOH ==> NaKT + HOH
mols KHT = grams/molar mass
mols HHT = moles NaOH.
M NaOH = moles/L NaOH.
You will have a M for each trial, then average the values you obtain.
Theory background of standardizing NaOH with KHP
What’s the concentration of the NaOH solution was found to be exactly??
To calculate the concentration of the standard sodium hydroxide (NaOH) solution, we will use the balanced chemical equation and the molar ratio between NaOH and KHC8H4O4 (potassium hydrogen phthalate).
The balanced chemical equation for the reaction between NaOH and KHC8H4O4 is:
NaOH + KHC8H4O4 -> NaKC8H4O4 + H2O
The molar ratio between NaOH and KHC8H4O4 is 1:1, meaning that one mole of NaOH reacts with one mole of KHC8H4O4.
First, we need to find the number of moles of KHC8H4O4 in each trial by using its molar mass. The molar mass of KHC8H4O4 can be calculated as follows:
Molar mass of KHC8H4O4 = (1 x molar mass of K) + (1 x molar mass of H) + (1 x molar mass of C8H4O4)
Molar mass of KHC8H4O4 = (1 x 39.10 g/mol) + (1 x 1.01 g/mol) + (1 x (12.01 g/mol x 8 + 1.01 g/mol x 4))
Molar mass of KHC8H4O4 = 204.22 g/mol
Using the given masses of KHC8H4O4 in each trial, we can calculate the number of moles for each trial:
Number of moles of KHC8H4O4 = Mass of KHC8H4O4 / Molar mass of KHC8H4O4
Trial 1:
Number of moles of KHC8H4O4 = 0.501 g / 204.22 g/mol
Trial 2:
Number of moles of KHC8H4O4 = 0.503 g / 204.22 g/mol
Trial 3:
Number of moles of KHC8H4O4 = 0.500 g / 204.22 g/mol
Next, we need to determine the number of moles of NaOH used in each trial. Since the molar ratio between NaOH and KHC8H4O4 is 1:1, the number of moles of NaOH is equal to the number of moles of KHC8H4O4.
Now, we can calculate the concentration of NaOH in each trial using the volume of NaOH solution used. The concentration can be determined using the formula:
Concentration (M) = Moles / Volume (L)
Trial 1:
Concentration of NaOH = Number of moles of NaOH / Volume of NaOH solution
Concentration of NaOH = Number of moles of NaOH / 15.22 mL
Trial 2:
Concentration of NaOH = Number of moles of NaOH / Volume of NaOH solution
Concentration of NaOH = Number of moles of NaOH / 15.11 mL
Trial 3:
Concentration of NaOH = Number of moles of NaOH / Volume of NaOH solution
Concentration of NaOH = Number of moles of NaOH / 15.10 mL
Finally, to calculate the average concentration of the standard NaOH solution, we can take the average of the three trial concentrations.
Average concentration of NaOH = (Concentration of NaOH in Trial 1 + Concentration of NaOH in Trial 2 + Concentration of NaOH in Trial 3) / 3