2Na + Cl2 → ?NaCl
In the reaction, sodium and chlorine combine to produce sodium chloride. In an instance when eight sodium chloride molecules are produced, how many diatomic chlorine molecules went into the reaction?
eight
one
two
four
Balance the equation by replacing the ? with a 2.
2Na + Cl2 → 2NaCl
The balanced equation allows you to use the coefficients to convert any amount of one ingredient to an equivalent amount of any other in the same equation. It's done like this.
8 NaCl molecules x (1 mol Cl2/2 moles NaCl) = 8*1/2 = ?
Looks like 4 to me.
dr bob is correct, the answer is 4
Z do you have the other answer...
Knock knock
Who's there?
Chlorine.
Chlorine who?
Chlorine is a diatomic element, so there must have been FOUR diatomic chlorine molecules that went into the reaction!
To determine the number of diatomic chlorine molecules that went into the reaction, we need to analyze the balanced equation:
2Na + Cl2 → 2NaCl
The coefficient in front of Cl2 indicates the number of diatomic chlorine molecules involved in the reaction. In this case, the coefficient is 1.
So, the answer is one diatomic chlorine molecule went into the reaction.