How much would a 10th dog have to weigh for the average weight in part (a) to be 250 pounds? Explain how you determined your answer.
70, 51, 65,65, 40, 7,70,22, 45
The average is: 54.375
I don't want the answer i just want a hint or something or just the steps to find it.
Also i neeed this answer RN. also thank u
250 lbs? with all those small dogs?
oh, well.
x + (sum of all the 9 weights) = 10*250
or
(x + 9*54.375)/10 = 250
It better be a horse!
what more do you want? I gave you two equivalent formulas to find x, the required weight.
you want the total weight of the 10 dogs to be 10 times the desired average.
Fr. thats what I said, It's a stupid question, for when talking abt dogs. lol, but anyways thanks for getting me a hint.
Can SOMEONE PLZ HELP ME!!! I need more guidance... Like i know that this is a stupid question but come on guys, plz help me
*Stupid question*
*stpid
Plz Help ME, Im desperate at this point tbh, and stressing hard abt this stpid portfolio, so can yall just help me.
ok jeez im sorry, i actually got the answerso thank u. btw also im sorry if i sounded desperate, or being hard to help, i was just stressed. But really thank u ooblek
To find the weight the 10th dog would have to be in order for the average weight to be 250 pounds, you can follow these steps:
1. Find the sum of the weights of the first 9 dogs: 70 + 51 + 65 + 65 + 40 + 7 + 70 + 22 + 45 = 435.
2. Subtract the sum obtained in step 1 from the desired average multiplied by 9 (the number of dogs considered so far): (250 * 9) - 435 = 2250 - 435 = 1815.
3. Divide the result obtained in step 2 by the total number of dogs (10): 1815 / 10 = 181.5.
Therefore, the 10th dog would have to weigh approximately 181.5 pounds for the average weight to be 250 pounds.
Note: The given data only includes the weights of 9 dogs, so it is not possible to determine the exact weight of the 10th dog based on the information provided.