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Fe2O3 + 3H2 → 2Fe + 3H2O
Calculate the mass of iron produced when 450.0 grams of iron (III) oxide react with hydrogen gas.
If you can please show me the work so I can learn how to do it

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Jake

  1. 2 Fe = 2 * 56 = 112 grams / 2 mols
    3 O = 3 * 16 = 48 g / 3 mols
    so
    Fe2O3 = 160 g/mol
    so
    450 g * ( 1 mol / 160 g) = 2.81 mols of iron oxide
    That will give me 2 * 2.81 = 5.63 mols of Fe
    5.63 * 56 g/mol = 315 grams of Fe

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    Anonymous

  2. The work by Anonymous is quite right and is presented very well. Here is a set of instructions that will work any stoichiometry problem.
    Step 1. Write and balance the equation.
    Step 2. Convert what you have into moles. moles = grams/molar mass OR if it is a solution then moles = molarity x liters or M x L = ?
    Step 3. Using the coefficients, as Anonymous did above, convert moles of what you have to moles of what you want.
    Step 4. If you want grams, then grams = moles x molar mass = ?
    Good luck.

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    DrBob222

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