In producing pure iron metal from its ore, iron(III) oxide and carbon (coke) must react according
to the following balanced chemical equation:
FerO-(s) + 3 C(s) › 2 Fe(s) + 3 CO (g)
Suppose 5.89 x10, mol of iron ore are consumed. How many moles of pure iron metal are produced?
A. 1.47 × 10 mol
B. 2.95 x 10, mol
C. 5.89 × 10 mol
D. 1.18 x 10+ mol
Well, let's break it down. According to the balanced equation, for every one mole of iron(III) oxide consumed, we get two moles of pure iron metal produced. So, if we have 5.89 x 10^(-6) moles of iron(III) oxide, we can multiply that by 2 to find the moles of pure iron metal produced.
5.89 x 10^(-6) mol x 2 = 1.18 x 10^(-5) mol
So, the answer is D. 1.18 x 10^(-5) mol. Now that's a whole lot of iron!