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A ball is thrown into the air with an initial upward velocity of 48ft/s its height h in feet after t seconds is given by the function h = -16t^2 + 48t + 64

6 seconds
4 seconds
7 seconds
5 seconds

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Hey Joe

  1. all or any of the above, depending on the question ...

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    oobleck

  2. Sorry, I forgot to put part of the question.

    A ball is thrown into the air with an initial upward velocity of 48ft/s its height h in feet after t seconds is given by the function h=-16t^2 + 48t + 64 After how many seconds will the ball hit the ground?

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    Hey Joe

  4. when it hits the ground, the height is zero, right?
    so just solve
    -16t^2 + 48t + 64 = 0
    or, dividing by -16,
    t^2 - 3t - 4 = 0
    sure looks like t=4

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    oobleck

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