A spinner is divided into eight equal sections, as shown. You spin the spinner twice. What is the probability that the arrow will stop in a yellow section both times?
1/8 * 1/8
assuming exactly one of the 8 sections is yellow
To find the probability of the arrow stopping in a yellow section both times, we need to know the total number of sections and the number of yellow sections.
We are given that the spinner is divided into eight equal sections. Let's denote the total number of sections as "total_sections" and set it equal to 8.
Next, we need to determine the number of yellow sections. Unfortunately, the question does not specify the number of yellow sections. We need this information to calculate the probability.
If you have the information about the number of yellow sections, you can divide that number by the total number of sections to find the probability of stopping in a yellow section on one spin. Then, you can multiply that probability by itself to find the probability of stopping in a yellow section twice in a row.
For example, if there are two yellow sections, the probability of stopping in a yellow section on one spin would be 2/8, and the probability of stopping in a yellow section twice would be (2/8) * (2/8) = 4/64 = 1/16.
Once you have the number of yellow sections, you can follow this method to calculate the probability.
To find the probability of the arrow stopping in a yellow section twice, we need to determine the total number of possible outcomes and the number of favorable outcomes.
1. Total outcomes: The spinner is divided into eight equal sections, so there are 8 possible outcomes for the first spin and 8 possible outcomes for the second spin. Therefore, the total number of possible outcomes is 8 * 8 = 64.
2. Favorable outcomes: The arrow needs to stop in a yellow section for both spins. There are 2 yellow sections out of the total 8 sections on the spinner. So, the number of favorable outcomes is 2 * 2 = 4.
3. Probability: The probability of an event occurring is calculated by dividing the number of favorable outcomes by the number of total outcomes. In this case, the probability is 4/64, which simplifies to 1/16.
Therefore, the probability that the arrow will stop in a yellow section both times is 1/16.