When black gunpowder explodes, potassium nitrate (KNO3), carbon, and sulfur react with each other to form nitrogen gas (N2), carbon dioxide gas (CO2), and solid potassium sulfide (K2S).
write the chemical equation
16KNO3 (s) + 24C (s) + S8 (s) yield 8N2 (g) + 24CO2 (g) + 8K2S
The chemical equation for the reaction of potassium nitrate (KNO3), carbon, and sulfur to form nitrogen gas (N2), carbon dioxide gas (CO2), and solid potassium sulfide (K2S) is as follows:
2KNO3 + 3C + S -> N2 + 3CO2 + K2S
To write the chemical equation for the reaction of black gunpowder exploding, we need to balance the equation by making sure that the number of atoms of each element is the same on both sides of the equation.
The reactants are potassium nitrate (KNO3), carbon (C), and sulfur (S). The products are nitrogen gas (N2), carbon dioxide gas (CO2), and solid potassium sulfide (K2S).
First, let's write the unbalanced equation:
KNO3 + C + S → N2 + CO2 + K2S
Now, let's balance the equation by counting the number of atoms on each side:
On the reactant side:
1 K atom on KNO3
1 N atom on KNO3
3 O atoms on KNO3
1 C atom on C
1 S atom on S
On the product side:
2 N atoms on N2
1 C atom on CO2
2 O atoms on CO2
2 K atoms on K2S
1 S atom on K2S
To balance the equation, we need to add coefficients in front of the chemical formulas to adjust the number of atoms:
2 KNO3 + 3 C + S → N2 + 3 CO2 + K2S
Now, the equation is balanced with the same number of atoms on both sides. The coefficients in front of the formulas represent the stoichiometric ratios between the reactants and products.
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