The atomic mass of nitrogen is 14 g/mol. The atomic mass of hydrogen is 1 g/mol. When the reaction produces 68 grams of ammonia, how many grams of nitrogen were present initially?

4
112
56
12

1. It compares the mass of the products to the mass of the reactants.

2. For every 3 moles of hydrogen gas, the reaction produces 2 moles of ammonia.
3. 56
4. 32 g/mol
5. 4

For those who want to see the questions with answers.

1. How does stoichiometry support the law of conservation of mass?

Ans: (A) It compares the mass of the products to the mass of the reactants.

2. Nitrogen gas and hydrogen gas react to produce ammonia according to the following equation.

N2 + 3H2 → 2NH3

Which ratio of components is correct?
Ans: (B) For every 3 moles of hydrogen gas, the reaction produces 2 moles of ammonia.

3. Nitrogen gas and hydrogen gas react to produce ammonia according to the following equation.

N2 + 3H2 → 2NH3

The atomic mass of nitrogen is 14 g/mol. The atomic mass of hydrogen is 1 g/mol. When the reaction produces 68 grams of ammonia, how many grams of nitrogen were present initially?

Ans: (C) 56

4.Elements A and B react according to the balanced equation shown.

2A + 3B2 → 2AB2

The molar mass of A is 8 g/mol. The molar mass of B is 12 g/mol. Which option shows the correct molar mass of AB2?
Ans: (B) 32g/mol

5.Hydrogen and oxygen react to produce water according to the following equation.

2H2 + O2 → 2H2O

The molar mass of hydrogen gas (H2) is 2 g/mol. The molar mass of oxygen gas (O2) is 32 g/mol. When the reaction starts with 64 grams of oxygen and a sufficient quantity of hydrogen, how many moles of water are produced?

5. (C) 4

i did it is correct 5/5 thanks for the help.

molar mass of NH3 = 14+3 = 17 grams/mol

68 grams / 17 grams/mol = 4 mols of NH3
that needs 2 mols of N2
2 * 2 * 14 = 56 grams of N2

i did it is right 100% honest

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I didn’t look at the answer at all - :))

Help is 100% correct

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