A person walks 17.0◦ north of east for 1.33

km. Another person walks due north and due
east to arrive at the same location.
How large is the east component of this
second path?
Answer in units of km.

1.33 sin17° = ____ km

1.33 cos 17

the two east components are the same if they end up the same distance east of the origin :)

north of east, not east of north as we scouts do it.

oops - my bad. Good catch

To solve this problem, we need to calculate the east component of the second path.

Let's denote the east component of the second path as 'E' (in km).

First, we need to determine the distance traveled by the first person in the eastward direction. We can do this by multiplying the total distance traveled (1.33 km) by the cosine of the angle they walked (17.0 degrees north of east).

Distance in eastward direction = Total distance * cosine(angle)
Distance in eastward direction = 1.33 km * cos(17.0°)

Next, we need to calculate the northward distance traveled by the second person to arrive at the same location. Since the first person walked due north, the second person must have traveled this same distance.

The eastward component of the second path is equal to the eastward component of the first path. Therefore, the eastward component of the second path is equal to the distance calculated earlier.

So, the east component of the second path is given by:

E = 1.33 km * cos(17.0°)

Calculating this value, we have:

E ≈ 1.33 km * 0.9501
E ≈ 1.264 km

Therefore, the east component of the second path is approximately 1.264 km.