The head of a pin has a diameter of 1 X 10^-4 meter. A bacterium has a diameter of 5 X 10-7 meter. How many bacteria that size would fit across the diameter of the pinhead?
in line across?
10 * 10^-5 / (5 * 10^-7) = 2 * 10^(-5+7) = 2 *10^2 = 200
To find out how many bacteria would fit across the diameter of the pinhead, we need to divide the diameter of the pinhead by the diameter of a bacterium.
1 X 10^-4 meter / 5 X 10^-7 meter = (1 / 5) X (10^-4 / 10^-7) = 0.2 X 10^3
Simplifying further:
0.2 X 10^3 = 2 X 10^2
Therefore, there would be approximately 200 bacteria of that size that could fit across the diameter of the pinhead.
To calculate how many bacteria of a given size can fit across the diameter of a pinhead, we can divide the diameter of the pinhead by the diameter of a bacterium.
Given:
Diameter of pinhead = 1 × 10^-4 meter
Diameter of bacterium = 5 × 10^-7 meter
To find the number of bacteria that can fit across the pinhead, we need to divide the diameter of the pinhead by the diameter of a bacterium:
Number of bacteria = Diameter of pinhead / Diameter of bacterium
Number of bacteria = (1 × 10^-4) / (5 × 10^-7)
To divide these numbers in scientific notation, we need to subtract the exponents:
Number of bacteria = (1 / 5) × 10^(-4 - (-7))
= (1 / 5) × 10^(-4 + 7)
= (1 / 5) × 10^3
= 1 × 10^3 / 5
= 200
Therefore, the number of bacteria that would fit across the diameter of the pinhead is 200.