Juma is x years if he is twice as old as Chris the sum of their ages in 10 years to come is 35
Find Chris age
Chris' age now --- x
Juma's age now ---- 2x
10 years from now:
Chris ---- x + 10
Juma ---- 2x + 10
x+10 + 2x+10 = 35
solve for x
3x +20 =35-20 3x÷15=5 then add 5 to 10 which is 15yrs
Let's set up equations to solve the problem step by step.
Let's assume Chris's age is y years.
According to the problem, Juma is twice as old as Chris, so we can write the equation:
x = 2y
Now, let's consider the sum of their ages in 10 years.
In 10 years, Juma's age will be (x + 10), and Chris's age will be (y + 10).
The problem states that the sum of their ages in 10 years is 35, so we can write the equation:
(x + 10) + (y + 10) = 35
Now, substitute the value of x from the first equation into the second equation:
(2y + 10) + (y + 10) = 35
Combine like terms:
3y + 20 = 35
Subtract 20 from both sides:
3y = 15
Divide both sides by 3:
y = 5
Therefore, Chris's age is 5 years.
To find Chris's age, we can start by setting up equations based on the given information.
Let's represent Juma's current age as x.
According to the information given, Juma is twice as old as Chris, so we can represent Chris's current age as x/2.
In 10 years, Juma's age will be x + 10.
Similarly, in 10 years, Chris's age will be (x/2) + 10.
The sum of their ages in 10 years is given as 35:
(x + 10) + ((x/2) + 10) = 35
Now we can solve this equation to find Chris's age:
Simplifying the equation:
x + (x/2) + 20 = 35
Multiplying through by 2 to remove the fraction:
2x + x + 40 = 70
Combining like terms:
3x + 40 = 70
Moving 40 to the other side of the equation:
3x = 30
Dividing both sides of the equation by 3:
x = 10
Therefore, Juma's current age is 10 years.
To find Chris's age, we can substitute the value of x back into the equation:
Chris's current age = x/2 = 10/2 = 5
Therefore, Chris's age is 5 years.