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Math trigonometric Identities
Is this correct? (sinx - cosx)^2 = 1 - 2sinxcosx LS = sin^2x - 2sinxcosx + cos^2x = 1 - cos^2x - 2sinxcosx + cos^2x = 1 - cos^2x + cos^2x - 2sinxcosx = 1 - 2sinxcosx LS = RS
asked by Anonymous on May 3, 2015 -
Math Trigonometric Identities
Is this correct? (sinx - cosx)^2 = 1 - 2sinxcosx LS = sin^2x - 2sinxcosx + cos^2x = 1 - cos^2x - 2sinxcosx + cos^2x = 1 - cos^2x + cos^2x - 2sinxcosx = 1 - 2sinxcosx LS = RS
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Prove the identity: 1-cos2x/sin2x = 1+tanx/1+cotx I simplified the RS to tanx. LS:(1-2cos²x+1)/2sinxcosx (2+2cos²x)/2sinxcosx How do I simplify the rest?
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