Out of 400 students in the final year in a senior secondary school,300 are offering chemistry.How many students are offering both biology and chemistry if only 70 students are offering neither biology nor chemistry.How many students are offering at least one of biology or chemistry.
I)300-x+x+190-x+70=400
490+70-x=400
560-x=400
-x=400-560
-x/-1=-160/-1
x=160
330
Well, it seems like this senior secondary school is quite the melting pot of subjects! Let's break it down:
We have 400 students in total, and out of those, 300 are offering chemistry. However, we know that there are 70 students who are not taking biology or chemistry.
To figure out how many students are offering both biology and chemistry, we need to subtract the students not taking any of these subjects from the total number of students taking chemistry.
So, let's do the math: 300 (students taking chemistry) - 70 (not taking either subject) = 230
Hence, 230 students are taking both biology and chemistry.
Now, to calculate the number of students taking at least one of these subjects, we can add the number of students taking biology to the number of students taking chemistry:
300 (students taking chemistry) + 230 (taking both) = 530
Therefore, there are 530 students taking at least one of biology or chemistry.
Hope that puts a smile on your face!
To find the number of students offering both biology and chemistry, we need to subtract the number of students offering neither biology nor chemistry from the total number of students offering chemistry.
Given:
Total number of students in the final year: 400.
Number of students offering chemistry: 300.
Number of students offering neither biology nor chemistry: 70.
To find the number of students offering both biology and chemistry, we can calculate it using the principle of inclusion-exclusion.
First, let's find the number of students offering at least one of biology or chemistry.
Total students offering at least one of biology or chemistry = Total students - Students offering neither biology nor chemistry
Total students offering at least one of biology or chemistry = 400 - 70 = 330
Now, let's find the number of students offering both biology and chemistry.
Number of students offering both biology and chemistry = Total students offering chemistry - Students offering neither biology nor chemistry
Number of students offering both biology and chemistry = 300 - 70 = 230
Therefore, 230 students are offering both biology and chemistry.
400-70 = 330 are offering something
No way to tell how many are doing both. Could be anything from 0-300