Methane burns in the presence of oxygen to create carbon dioxide and water explain in detail the steps you would need to take To write a balanced equation for the chemical reaction you need four steps
oobleck and I have done three of these stoichiometry problems for you. I'll be glad to check your work if you will post it.
Thank you. I’m working on it now. I’m really struggling in this unit.
Steps to solve stoichiometry problems. This will do them all.
1. Write and balance the equation.
2. Convert what you have to moles. For solids it is mols = grams/molar mass. For solution it is moles = molarity x liters.
3. Using the coefficients in the balanced equation (from step 1), convert moles of what you have to moles of what you want.
4. Depends upon the question. If you want moles you have that and you're done. If you want grams of the product/reactant then g = mols x molar mass. If you want concentration it is M = moles/L of solution.
Look at the earlier SO2/CO problem.
1. You were given the balanced equation.
2. You converted what you had (17 g CO) to moles. moles CO = 17/28.01 = 0.606 mols CO.
3. Convert mols of what you have (0.606 mols CO) to moles of what you want (moles SO2). 0.606 x ((2 mols SO2/4 moles CO) = 0.303 moles SO2.
4. You're done. If the problem asked for grams SO2, then mols SO2 x molar mass SO2 = 0.303 x 64 g SO2/mole SO2) = about 19 g SO2.
Hope this helps. Don't let chemistry get you down.
To write a balanced equation for the combustion of methane, you need to follow these four steps:
1. Identify the reactants and products: The reactants in this reaction are methane (CH4) and oxygen (O2). The products are carbon dioxide (CO2) and water (H2O).
2. Determine the number of atoms for each element in the reactants and products: In methane, there is one carbon atom and four hydrogen atoms. In oxygen, there are two oxygen atoms. In carbon dioxide, there is one carbon atom and two oxygen atoms. In water, there are two hydrogen atoms and one oxygen atom.
3. Balance the carbon and hydrogen atoms: Start by balancing the carbon and hydrogen atoms. Since there is only one carbon atom in methane, we place a coefficient of 1 in front of CO2. The balanced equation becomes:
CH4 + O2 -> CO2 + H2O
Now, we balance the hydrogen atoms. Since there are four hydrogen atoms in methane and only two in water, we need to put a coefficient of 2 in front of H2O:
CH4 + O2 -> CO2 + 2H2O
4. Balance the oxygen atoms: Now we look at the number of oxygen atoms. In methane, there is one oxygen atom already present in the form of O2. In carbon dioxide, there are two oxygen atoms. In water, there are two oxygen atoms as well. So, in total, there are four oxygen atoms on the right side of the equation. To balance this, we put a coefficient of 2 in front of O2:
CH4 + 2O2 -> CO2 + 2H2O
And there you have it, the balanced equation for the combustion of methane is:
Methane (CH4) + Oxygen (O2) -> Carbon Dioxide (CO2) + Water (H2O)