a ball rolls off a table 1.36 m tall. It lands 3 m from the base of the table. What is the horizontal velocity of the ball when it left the table?
how long does it take to fall 1.36m?
4.9t^2 = 1.3
so the horizontal velocity v can be found via
1.3v = 3
(1/2) g t^2 = 1.36
4.9 t^2 = 1.36
t^2 = 0.27755
t = 0.527 second
u t = 3 meters
so
u = 3 / 0.527 = 5.69 m/s