Lithium (Li) bonds with another atom to form a stable molecule with formula LiX. Based on groups in the periodic table, which atom could represent X?
oxygen (O)
boron (B)
potassium (K)
bromine (Br)
I think it C
I'm pretty sure is Bromine. Lithium Bromide is an ionic bond, but the others don't bond with Lithium.
Oh, sorry, but that answer is a bit Li-to the wrong side. The correct choice is bromine (Br). Li forms a stable molecule with bromine to make LiBr. So, bromine steals Li's heart in this case!
The correct answer is bromine (Br). Lithium, being in Group 1 of the periodic table, has one valence electron and tends to lose it to form a stable ion. Bromine, on the other hand, is in Group 17, also known as the halogens, and has seven valence electrons. Bromine tends to gain one electron to complete its valence shell and achieve stability. Therefore, when lithium reacts with bromine, Li+ forms a bond with Br- to create the stable molecule LiBr.
To determine the atom that could represent X in the stable molecule LiX, we need to consider the groups in the periodic table.
Lithium (Li) belongs to Group 1, which is known as the alkali metals group. The alkali metals readily form ionic bonds with other elements since they have one valence electron that they can easily lose to achieve a stable electron configuration.
Based on the options given, each atom belongs to a specific group:
- Oxygen (O) belongs to Group 16, also known as the chalcogens.
- Boron (B) belongs to Group 13, also known as the boron group.
- Potassium (K) belongs to Group 1, like lithium. Both are alkali metals.
- Bromine (Br) belongs to Group 17, known as the halogens.
To form a stable molecule with lithium, the atom X needs to accept the valence electron from lithium to achieve stability. Therefore, we need to look for an atom in Group 17, which readily accepts an electron.
Out of the options given, bromine (Br) belongs to Group 17 and can easily accept the valence electron from lithium to form a stable molecule with the formula LiBr.
So, the correct answer is bromine (Br).