A hockey puck has a coefficient of kinetic friction of μ = .10. If the puck feels a normal force (FN) of 5 N, what is the frictional force that acts on the puck?
1 * 5 = 5N
0.10 * 5 = 0.5 Newtons
assuming that the force is normal to the ice (gravity not a stick or something)
To find the frictional force acting on the hockey puck, you can use the formula:
Frictional force (Ff) = μ * FN
Given that the coefficient of kinetic friction (μ) is 0.10 and the normal force (FN) is 5 N, you can substitute the values into the formula:
Ff = 0.10 * 5
Ff = 0.5 N
Therefore, the frictional force acting on the hockey puck is 0.5 N.
To find the frictional force acting on the hockey puck, we can use the formula:
frictional force = coefficient of kinetic friction × normal force
Given:
Coefficient of kinetic friction (μ) = 0.10
Normal force (FN) = 5 N
Now, we can substitute these values into the formula to find the frictional force:
Frictional force = 0.10 × 5
Multiplying the values together:
Frictional force = 0.5 N
Therefore, the frictional force acting on the hockey puck is 0.5 N.