write the equation of the line passing through (-6, -9) and (0, -9).
Can some one help me with this please.
When I tried to solve this problem I got a slope of 0 and I do not know what to do from there
I notice the y is constant, so there is zero slope. The equation of the line then is y= mx+b= 0+b and b is -9
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To find the equation of a line passing through two given points, you can use the slope-intercept form of the equation, which is y = mx + b. You have already correctly determined the slope is 0 since the y-values of both points are the same.
To find the y-intercept (b), you can plug one of the given points into the equation. Let's use the second point (0, -9):
y = mx + b
-9 = 0 * 0 + b
-9 = b
Now we know that the y-intercept (b) is -9. So the equation of the line passing through (-6, -9) and (0, -9) is y = 0x - 9, which simplifies to y = -9.