Acar accidentally rolls off acliff as it leaves the cliff it has as horizontal velocity of 15m/s it hits the ground 45m from edge of the sea what is the height of cliff?(use g=10m/s square)

Use horizontal motion to find the time, t, it took the car to fall:

t = 45 m / 15 m/s = 3 s
Use vertical motion to find the height of the cliff, d:
d = vit + (1/2)at ²
d = 0 + (1/2)(10 m/s ²)(3 s) ²
d = 45 m

Thank you Coolcat :)

Saves me some trouble.

To find the height of the cliff, we can use the equations of motion. Let's break down the information given in the problem:

Initial horizontal velocity of the car (u) = 15 m/s
Time taken to hit the ground (t) = ?
Horizontal distance traveled (R) = 45 m
Acceleration due to gravity (g) = 10 m/s^2

Using the equation of motion for horizontal distance, we have:

R = u * t

Substituting the given values, we can solve for time (t):

45 m = 15 m/s * t

Dividing both sides of the equation by 15 m/s, we have:

t = 45 m / 15 m/s
t = 3 s

Now, since we know the time taken to hit the ground, we can use the equation of motion for vertical distance to find the height of the cliff:

h = u * t + (1/2) * g * t^2

Substituting the given values, we have:

h = 0 + (1/2) * 10 m/s^2 * (3 s)^2
h = 0 + (1/2) * 10 m/s^2 * 9 s^2
h = 0 + 45 m
h = 45 m

Therefore, the height of the cliff is 45 meters.