mimo has some Php 10 and Php 5 coins .The amount of these coins is at most Php 750. Suppose there are 50 Php 5 coins, what could possibly be the number of Php 10 coin?
number of Php 10 ---- x
number of Php 5 ----- y
10x + 5y ≤ 750
2x + y ≤ 150
if y = 50
2x + 50 ≤ 150
2x ≤ 100
x ≤ 50
mimo has some 10 and 5 coins. the total amount of these coins is at most 150. suppose there are 10 5 coins. what could possibly be the number of 10 coin? what is asked?
Paki sagot naman po
To determine the possible number of Php 10 coins, we need to consider the total amount and the number of Php 5 coins given.
Let's assume the number of Php 10 coins as 'x'.
The value of one Php 10 coin is 10.
The value of one Php 5 coin is 5.
Given:
- The total amount should be at most Php 750.
- There are 50 Php 5 coins.
So, we can set up the equation:
10x + 5(50) ≤ 750
Simplifying this equation, we get:
10x + 250 ≤ 750
Now, let's solve for 'x':
10x ≤ 750 - 250
10x ≤ 500
x ≤ 500 / 10
x ≤ 50
Therefore, the possible number of Php 10 coins (x) could be any number less than or equal to 50.