3loga = 1 loga = 1/3 a = 10^(1/3) Or maybe you meant log^2(a) + loga = 1 log^2(a) + loga - 1 = 0 loga = (-1±√5)/2 a = 10^((-1+√5)/2)
2y+y=1 2y+y=1 3y=1.then y=1/3.but loga=1/3 a=10^1/3.
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