NaPO4 + PbNO3 = what? balance
2 Na3PO4 + 3 Pb(NO3)2 = 6 NaNO3 + Pb3(PO4)2
The compound formulas are not written properly. You start out with Na3PO4 and Pb(NO3)2. The products are NaNO3 and a precipitate, Pb3(PO4)2
Try balancing those. Each Na3PO4 is going to make three NaPO4's
I think this is a double replacement reaction, just in case you wanted to know.
thanks
Buddy got it right.
I meant to write
"each Na3PO4 is going to make three NaNO3's"
To balance the chemical equation NaPO4 + Pb(NO3)2, we need to adjust the coefficients in front of each compound so that the number of atoms of each element is the same on both sides of the equation.
Step 1: Count the number of atoms of each element on each side of the equation.
On the left side:
- Na: 1
- P: 1
- O: 4
- Pb: 0
- N: 0
On the right side:
- Na: 0
- P: 0
- O: (3 x 2) = 6 (since there are two NO3 groups)
- Pb: 1
- N: (2 x 2) = 4 (since there are two NO3 groups)
Step 2: Determine which element or elements are not balanced.
In this case, the elements that are not balanced are Na, P, Pb, and N.
Step 3: Start balancing the equation by choosing an element to balance first.
Since there is only one Pb on the right side, let's start by balancing Pb.
Step 4: Add a coefficient in front of the compound containing Pb to balance the number of Pb atoms.
Adding a coefficient of 2 in front of Pb(NO3)2, we have:
NaPO4 + 2Pb(NO3)2
Now, for Pb:
- On the left side: 0
- On the right side: (2 x 1) = 2
Step 5: Continue balancing the remaining elements.
Next, let's balance Na. Since there is only one Na on the left side, we will add a coefficient of 2 in front of NaPO4:
2NaPO4 + 2Pb(NO3)2
Now, for Na:
- On the left side: (2 x 2) = 4
- On the right side: 0
Step 6: Lastly, balance P and N. Since there is only one P and two NO3 groups on the left side, we will add a coefficient of 2 in front of NaPO4:
2NaPO4 + 2Pb(NO3)2
Now, for P:
- On the left side: (2 x 1) = 2
- On the right side: (2 x 2) = 4
And for N:
- On the left side: 0
- On the right side: (2 x 2 x 1) = 4
Step 7: Verify that all elements are balanced.
- Na: 2 on the left side = 2 on the right side
- P: 2 on the left side = 2 on the right side
- O: (2 x 4) = 8 on the left side = (2 x 3 x 2) = 12 on the right side
- Pb: 0 on the left side = 2 on the right side
- N: 0 on the left side = (2 x 2) = 4 on the right side
To balance the equation, we have:
2NaPO4 + 2Pb(NO3)2 ⟶ Pb2(PO4)2 + 2Na(NO3)
Therefore, NaPO4 + Pb(NO3)2 ⟶ Pb2(PO4)2 + 2Na(NO3) is the balanced equation.