Fiona finds 1 shell on her first day at the beach.every day that week,she finds twice as many shells as she did the day before.how many shells does Fiona find on the seventh day?
term(n) = a r^(n-1), your a = 1, and your r = 2
term(7) = 1(2)^6 = 64
or
you could just make a list of the terms
To find out how many shells Fiona finds on the seventh day, we need to calculate the number of shells she finds each day.
On the second day, Fiona finds twice as many shells as she did on the first day: 1 * 2 = 2 shells.
On the third day, Fiona finds twice as many shells as she did on the second day: 2 * 2 = 4 shells.
On the fourth day, Fiona finds twice as many shells as she did on the third day: 4 * 2 = 8 shells.
On the fifth day, Fiona finds twice as many shells as she did on the fourth day: 8 * 2 = 16 shells.
On the sixth day, Fiona finds twice as many shells as she did on the fifth day: 16 * 2 = 32 shells.
On the seventh day, Fiona finds twice as many shells as she did on the sixth day: 32 * 2 = 64 shells.
Therefore, Fiona finds 64 shells on the seventh day.
To find out how many shells Fiona finds on the seventh day, we need to follow the pattern given in the question.
On the first day, Fiona finds 1 shell.
On the second day, she finds twice as many shells as the day before, which is 1 x 2 = 2 shells.
On the third day, she finds twice as many shells as the day before, which is 2 x 2 = 4 shells.
On the fourth day, she finds twice as many shells as the day before, which is 4 x 2 = 8 shells.
On the fifth day, she finds twice as many shells as the day before, which is 8 x 2 = 16 shells.
On the sixth day, she finds twice as many shells as the day before, which is 16 x 2 = 32 shells.
On the seventh day, she finds twice as many shells as the day before, which is 32 x 2 = 64 shells.
Therefore, Fiona finds 64 shells on the seventh day.