△ABC (A=2,1 B=2,2 C=4,2) is dilated by a scale factor of 2 using the origin
as the center of dilation.
What are the new coordinates of △A'B'C'?
just multiply all the coordinates by 2,
and then review dilations.
To find the new coordinates of the triangle △A'B'C' after it is dilated by a scale factor of 2 using the origin as the center of dilation, we need to multiply the coordinates of each vertex by the scale factor.
Let's start by finding the new coordinates of point A'.
The original coordinates of A are (2, 1). To dilate this point by a scale factor of 2, we need to multiply both the x-coordinate and the y-coordinate by 2.
So, the x-coordinate of A' is 2 * 2 = 4, and the y-coordinate of A' is 1 * 2 = 2.
Therefore, the new coordinates of point A' are (4, 2).
Now, let's find the new coordinates of point B'.
The original coordinates of B are (2, 2). Again, multiplying both the x-coordinate and the y-coordinate by 2:
The x-coordinate of B' is 2 * 2 = 4, and the y-coordinate of B' is 2 * 2 = 4.
Therefore, the new coordinates of point B' are (4, 4).
Lastly, let's find the new coordinates of point C'.
The original coordinates of C are (4, 2). Applying the same process:
The x-coordinate of C' is 4 * 2 = 8, and the y-coordinate of C' is 2 * 2 = 4.
Therefore, the new coordinates of point C' are (8, 4).
In summary, the new coordinates of triangle △A'B'C' after dilating with a scale factor of 2 using the origin as the center of dilation are:
A' = (4, 2)
B' = (4, 4)
C' = (8, 4).