A ship sail from town A(0°,20°W) to town B(10°N,20°W) at 16 knots. If it leaves town A at 8am on Tuesday, when will it reach town B?

I need help

Luckily went straight north so on a meridian (which is a great circle) where one minute of arc is one nautical mile.

10 degrees * 60 minutes/degree = 600 nautical miles
600 miles at 1 hour / 16 miles = 37 1/2 hours
that is one 24 hour day + 13.5 hours
8 am Wednesday + 13.5hours
so 8 pm wed + 1.5 hours
9:30 Wed evening

... and that is the first time in my life that I have seen a math question about navigation worded correctly !

To determine when the ship will reach town B, we need to calculate the time it takes for the ship to travel the distance between town A and town B at a speed of 16 knots.

1. Calculate the distance between town A and town B:
- The latitude of town A is 0°, and the latitude of town B is 10°N. The difference in latitude is 10°.
- Since the distance between two latitudes is approximately 60 nautical miles per degree of latitude, the distance between town A and town B is 10° * 60 nautical miles = 600 nautical miles.

2. Determine the time it takes to travel the distance:
- The speed of the ship is given as 16 knots.
- Time = Distance / Speed
- Time = 600 nautical miles / 16 knots = 37.5 hours.

3. Calculate the arrival time:
- The ship leaves town A at 8 am on Tuesday, so we need to add 37.5 hours to that time.
- Since there are 24 hours in a day, we can divide 37.5 hours by 24 to determine the number of days.
- 37.5 hours / 24 hours = 1.5625 days.
- Add 1.5625 days to the departure day of Tuesday, which gives us Wednesday afternoon.
- To determine the exact time, we can multiply the decimal part (0.5625) by 24 hours to convert it into hours.
- 0.5625 * 24 hours = 13.5 hours.

Therefore, the ship will reach town B on Wednesday at 8 am + 13.5 hours = 9:30 pm.