A student walks and jogs to college each day. She averages 5km/h walking and 9km/h jogging. The distance from home to college is 8km and she makes the trip in 1 hour. How far does the student jog.

To set up the equation I got:

5(x)+9(8-x)=8

5x+72-9x=8
-4x=-64
x=16

but this gives me a negative number for the walking.

WHAT IS THE CORRECT WAY TO SET UP AND SOLVE THE EQUATION?

You x is TIME, not distance

5(x) + 9 (1-x) = 8
5 x + 9 -9 x = 8
- 4x = - 1
x = 1/4 or 15 minutes walking
3/4 hour jogging
3/4 * 9 = 27/4 = 6.75 km jogging

OOOH! I see, thanks for the help!

i need help with my homewok please help out and is hard that why i am asking help.

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To correctly set up and solve this equation, you need to consider the amount of time the student spends walking and jogging. Let's denote the time spent walking as "t" and the time spent jogging as "1 - t" (since the entire trip takes 1 hour).

Since the speed is distance over time, the distance traveled while walking is 5t (since the average walking speed is 5 km/h), and the distance traveled while jogging is 9(1 - t) (since the average jogging speed is 9 km/h).

The sum of these distances should equal the total distance of 8 km, so we can set up the equation:

5t + 9(1 - t) = 8.

Now, let's solve this equation step by step:

5t + 9 - 9t = 8.
-4t + 9 = 8.
-4t = 8 - 9.
-4t = -1.
t = -1 / -4.
t = 1/4.

We get t = 1/4, which means the student spends 1/4 of an hour, or 15 minutes, walking. Since the total time for the trip is 1 hour, the student must spend 45 minutes jogging.

To find the distance jogged, we can multiply the jogging speed (9 km/h) by the time spent jogging:

Distance jogged = 9 km/h * (3/4 hour) = 27/4 km = 6.75 km.

Therefore, the student jogs a distance of 6.75 km.