3. Imagine a scenario where an animal’s force is pushing itself forward 5 N. Friction is pushing it 4 N backward. Gravity is pushing it 10 N down. And the animal is pushing itself 10 N Up. Describe the movement of the animal.
A. It only moves forward because there is a net force forward.
B. It moves 29N because that’s the net force.
C. It moves 10 Down then 10 Up as those are the greatest forces acting on the animal.
D. It moves forward and upward because those are the greatest net forces.
A. It only moves forward because there is a net force forward. Idk if this is the right answer but hopefully it helps! ^^
D. It moves forward and upward because those are the greatest net forces.
Well, this animal is having quite a party of forces! It's like a tug of war, but instead of a rope, we have forces pushing in different directions. The force pushing the animal forward is 5N, but the friction is being like a party pooper and pushing back with 4N. However, the animal is not one to give up easily, so it pushes itself upward with a 10N force, defying gravity. With all these force shenanigans happening, the result is that the animal has a greater net force pushing it forward and upward, allowing it to move in that direction. So, it's like the animal is saying, "Move aside, backward forces and gravity, I'm moving forward and upward!"
The correct answer is A. It only moves forward because there is a net force forward.
To determine the movement of the animal, we need to calculate the net force acting on it. Net force is the vector sum of all the forces acting on an object.
In this scenario, we have:
Force pushing the animal forward = 5 N
Force of friction pushing the animal backward = 4 N
Force of gravity pushing the animal down = 10 N
Force of the animal pushing itself upward = 10 N
To calculate the net force, we subtract the backward forces from the forward forces:
Net force = (5 N - 4 N) = 1 N
Since the net force is positive and in the forward direction, the animal will only move forward. The other forces (gravity and the animal pushing itself) are balanced and do not contribute to the net force, so the animal will not move up or down.
To determine the movement of the animal, we need to calculate the net force acting on the animal. Net force is the vector sum of all the individual forces acting on an object.
In this scenario, the animal is experiencing four forces:
1. Its own force pushing it forward with 5 N (let's call this F1).
2. Friction pushing it backward with 4 N (let's call this F2).
3. Gravity pushing it downward with 10 N (let's call this F3).
4. The animal pushing itself upward with 10 N (let's call this F4).
To find the net force, we need to consider the direction of each force. Forces in the same direction will add up, and forces in opposite directions will subtract.
Now, let's calculate the net force:
Forward force (F1) = 5 N
Backward force (F2) = 4 N
Downward force (F3) = 10 N
Upward force (F4) = 10 N
Net force = (F1 + F4) - (F2 + F3)
= (5 N + 10 N) - (4 N + 10 N)
= 15 N - 14 N
= 1 N
The net force acting on the animal is equal to 1 N.
So, based on the net force of 1 N, the movement of the animal will be as follows:
A. It only moves forward because there is a net force forward.
Therefore, option A is the correct answer.