What volume of .100 M NaOH will react completely with 21.00 mL of .500 M HCl?
Vb*ConcBase= Vacid*ConcAcid
Solve for Vb.
21.00 mL x .500 M HCl = 1.05e1
1.05e1 / .100 M NaOH = 1.05e2
right.
Not quite. Let me explain the correct calculation.
To find the volume of the NaOH solution (Vb) needed to react completely with a given volume of the HCl solution (Vacid) and concentration of HCl (ConcAcid), we can use the formula: Vb * ConcBase = Vacid * ConcAcid. In this case, the HCl is the acid and NaOH is the base.
Given:
Vacid = 21.00 mL
ConcAcid = 0.500 M
ConcBase = 0.100 M
Using the formula: Vb * ConcBase = Vacid * ConcAcid, we can solve for Vb:
Vb = (Vacid * ConcAcid) / ConcBase
Substituting the given values:
Vb = (21.00 mL * 0.500 M) / 0.100 M
Vb = 105.00 mL
Therefore, the volume of 0.100 M NaOH solution required to react completely with 21.00 mL of 0.500 M HCl is 105.00 mL.